Optimal. Leaf size=227 \[ -\frac {b p}{2 a d x}-\frac {b^2 p \log (x)}{2 a^2 d}-\frac {b e p \log (x)}{a d^2}+\frac {b^2 p \log (a+b x)}{2 a^2 d}+\frac {b e p \log (a+b x)}{a d^2}-\frac {\log \left (c (a+b x)^p\right )}{2 d x^2}+\frac {e \log \left (c (a+b x)^p\right )}{d^2 x}+\frac {e^2 \log \left (-\frac {b x}{a}\right ) \log \left (c (a+b x)^p\right )}{d^3}-\frac {e^2 \log \left (c (a+b x)^p\right ) \log \left (\frac {b (d+e x)}{b d-a e}\right )}{d^3}-\frac {e^2 p \text {Li}_2\left (-\frac {e (a+b x)}{b d-a e}\right )}{d^3}+\frac {e^2 p \text {Li}_2\left (1+\frac {b x}{a}\right )}{d^3} \]
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Rubi [A]
time = 0.15, antiderivative size = 227, normalized size of antiderivative = 1.00, number of steps
used = 14, number of rules used = 10, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.476, Rules used = {46, 2463,
2442, 36, 29, 31, 2441, 2352, 2440, 2438} \begin {gather*} -\frac {e^2 p \text {PolyLog}\left (2,-\frac {e (a+b x)}{b d-a e}\right )}{d^3}+\frac {e^2 p \text {PolyLog}\left (2,\frac {b x}{a}+1\right )}{d^3}-\frac {b^2 p \log (x)}{2 a^2 d}+\frac {b^2 p \log (a+b x)}{2 a^2 d}+\frac {e^2 \log \left (-\frac {b x}{a}\right ) \log \left (c (a+b x)^p\right )}{d^3}-\frac {e^2 \log \left (c (a+b x)^p\right ) \log \left (\frac {b (d+e x)}{b d-a e}\right )}{d^3}+\frac {e \log \left (c (a+b x)^p\right )}{d^2 x}-\frac {\log \left (c (a+b x)^p\right )}{2 d x^2}-\frac {b e p \log (x)}{a d^2}+\frac {b e p \log (a+b x)}{a d^2}-\frac {b p}{2 a d x} \end {gather*}
Antiderivative was successfully verified.
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Rule 29
Rule 31
Rule 36
Rule 46
Rule 2352
Rule 2438
Rule 2440
Rule 2441
Rule 2442
Rule 2463
Rubi steps
\begin {align*} \int \frac {\log \left (c (a+b x)^p\right )}{x^3 (d+e x)} \, dx &=\int \left (\frac {\log \left (c (a+b x)^p\right )}{d x^3}-\frac {e \log \left (c (a+b x)^p\right )}{d^2 x^2}+\frac {e^2 \log \left (c (a+b x)^p\right )}{d^3 x}-\frac {e^3 \log \left (c (a+b x)^p\right )}{d^3 (d+e x)}\right ) \, dx\\ &=\frac {\int \frac {\log \left (c (a+b x)^p\right )}{x^3} \, dx}{d}-\frac {e \int \frac {\log \left (c (a+b x)^p\right )}{x^2} \, dx}{d^2}+\frac {e^2 \int \frac {\log \left (c (a+b x)^p\right )}{x} \, dx}{d^3}-\frac {e^3 \int \frac {\log \left (c (a+b x)^p\right )}{d+e x} \, dx}{d^3}\\ &=-\frac {\log \left (c (a+b x)^p\right )}{2 d x^2}+\frac {e \log \left (c (a+b x)^p\right )}{d^2 x}+\frac {e^2 \log \left (-\frac {b x}{a}\right ) \log \left (c (a+b x)^p\right )}{d^3}-\frac {e^2 \log \left (c (a+b x)^p\right ) \log \left (\frac {b (d+e x)}{b d-a e}\right )}{d^3}+\frac {(b p) \int \frac {1}{x^2 (a+b x)} \, dx}{2 d}-\frac {(b e p) \int \frac {1}{x (a+b x)} \, dx}{d^2}-\frac {\left (b e^2 p\right ) \int \frac {\log \left (-\frac {b x}{a}\right )}{a+b x} \, dx}{d^3}+\frac {\left (b e^2 p\right ) \int \frac {\log \left (\frac {b (d+e x)}{b d-a e}\right )}{a+b x} \, dx}{d^3}\\ &=-\frac {\log \left (c (a+b x)^p\right )}{2 d x^2}+\frac {e \log \left (c (a+b x)^p\right )}{d^2 x}+\frac {e^2 \log \left (-\frac {b x}{a}\right ) \log \left (c (a+b x)^p\right )}{d^3}-\frac {e^2 \log \left (c (a+b x)^p\right ) \log \left (\frac {b (d+e x)}{b d-a e}\right )}{d^3}+\frac {e^2 p \text {Li}_2\left (1+\frac {b x}{a}\right )}{d^3}+\frac {(b p) \int \left (\frac {1}{a x^2}-\frac {b}{a^2 x}+\frac {b^2}{a^2 (a+b x)}\right ) \, dx}{2 d}-\frac {(b e p) \int \frac {1}{x} \, dx}{a d^2}+\frac {\left (b^2 e p\right ) \int \frac {1}{a+b x} \, dx}{a d^2}+\frac {\left (e^2 p\right ) \text {Subst}\left (\int \frac {\log \left (1+\frac {e x}{b d-a e}\right )}{x} \, dx,x,a+b x\right )}{d^3}\\ &=-\frac {b p}{2 a d x}-\frac {b^2 p \log (x)}{2 a^2 d}-\frac {b e p \log (x)}{a d^2}+\frac {b^2 p \log (a+b x)}{2 a^2 d}+\frac {b e p \log (a+b x)}{a d^2}-\frac {\log \left (c (a+b x)^p\right )}{2 d x^2}+\frac {e \log \left (c (a+b x)^p\right )}{d^2 x}+\frac {e^2 \log \left (-\frac {b x}{a}\right ) \log \left (c (a+b x)^p\right )}{d^3}-\frac {e^2 \log \left (c (a+b x)^p\right ) \log \left (\frac {b (d+e x)}{b d-a e}\right )}{d^3}-\frac {e^2 p \text {Li}_2\left (-\frac {e (a+b x)}{b d-a e}\right )}{d^3}+\frac {e^2 p \text {Li}_2\left (1+\frac {b x}{a}\right )}{d^3}\\ \end {align*}
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Mathematica [A]
time = 0.12, size = 188, normalized size = 0.83 \begin {gather*} -\frac {\frac {2 b d e p (\log (x)-\log (a+b x))}{a}+\frac {b d^2 p (a+b x \log (x)-b x \log (a+b x))}{a^2 x}+\frac {d^2 \log \left (c (a+b x)^p\right )}{x^2}-\frac {2 d e \log \left (c (a+b x)^p\right )}{x}-2 e^2 \log \left (-\frac {b x}{a}\right ) \log \left (c (a+b x)^p\right )+2 e^2 \log \left (c (a+b x)^p\right ) \log \left (\frac {b (d+e x)}{b d-a e}\right )+2 e^2 p \text {Li}_2\left (\frac {e (a+b x)}{-b d+a e}\right )-2 e^2 p \text {Li}_2\left (1+\frac {b x}{a}\right )}{2 d^3} \end {gather*}
Antiderivative was successfully verified.
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Maple [C] Result contains higher order function than in optimal. Order 9 vs. order
4.
time = 0.48, size = 850, normalized size = 3.74
method | result | size |
risch | \(-\frac {b e p \ln \left (x \right )}{a \,d^{2}}+\frac {b e p \ln \left (b x +a \right )}{a \,d^{2}}-\frac {p \,e^{2} \dilog \left (\frac {b x +a}{a}\right )}{d^{3}}+\frac {p \,e^{2} \dilog \left (\frac {\left (e x +d \right ) b +a e -b d}{a e -b d}\right )}{d^{3}}+\frac {b^{2} p \ln \left (b x +a \right )}{2 a^{2} d}+\frac {\ln \left (\left (b x +a \right )^{p}\right ) e}{d^{2} x}+\frac {i \pi \mathrm {csgn}\left (i c \left (b x +a \right )^{p}\right )^{2} \mathrm {csgn}\left (i c \right ) e^{2} \ln \left (x \right )}{2 d^{3}}-\frac {\ln \left (\left (b x +a \right )^{p}\right ) e^{2} \ln \left (e x +d \right )}{d^{3}}+\frac {\ln \left (\left (b x +a \right )^{p}\right ) e^{2} \ln \left (x \right )}{d^{3}}-\frac {\ln \left (c \right ) e^{2} \ln \left (e x +d \right )}{d^{3}}+\frac {\ln \left (c \right ) e^{2} \ln \left (x \right )}{d^{3}}+\frac {\ln \left (c \right ) e}{d^{2} x}-\frac {i \pi \,\mathrm {csgn}\left (i \left (b x +a \right )^{p}\right ) \mathrm {csgn}\left (i c \left (b x +a \right )^{p}\right ) \mathrm {csgn}\left (i c \right ) e^{2} \ln \left (x \right )}{2 d^{3}}+\frac {i \pi \,\mathrm {csgn}\left (i \left (b x +a \right )^{p}\right ) \mathrm {csgn}\left (i c \left (b x +a \right )^{p}\right ) \mathrm {csgn}\left (i c \right ) e^{2} \ln \left (e x +d \right )}{2 d^{3}}-\frac {i \pi \,\mathrm {csgn}\left (i \left (b x +a \right )^{p}\right ) \mathrm {csgn}\left (i c \left (b x +a \right )^{p}\right ) \mathrm {csgn}\left (i c \right ) e}{2 d^{2} x}-\frac {\ln \left (c \right )}{2 d \,x^{2}}-\frac {p \,e^{2} \ln \left (x \right ) \ln \left (\frac {b x +a}{a}\right )}{d^{3}}+\frac {p \,e^{2} \ln \left (e x +d \right ) \ln \left (\frac {\left (e x +d \right ) b +a e -b d}{a e -b d}\right )}{d^{3}}+\frac {i \pi \,\mathrm {csgn}\left (i \left (b x +a \right )^{p}\right ) \mathrm {csgn}\left (i c \left (b x +a \right )^{p}\right )^{2} e}{2 d^{2} x}-\frac {i \pi \mathrm {csgn}\left (i c \left (b x +a \right )^{p}\right )^{2} \mathrm {csgn}\left (i c \right ) e^{2} \ln \left (e x +d \right )}{2 d^{3}}-\frac {b p}{2 x a d}-\frac {b^{2} p \ln \left (x \right )}{2 a^{2} d}-\frac {\ln \left (\left (b x +a \right )^{p}\right )}{2 d \,x^{2}}-\frac {i \pi \,\mathrm {csgn}\left (i \left (b x +a \right )^{p}\right ) \mathrm {csgn}\left (i c \left (b x +a \right )^{p}\right )^{2} e^{2} \ln \left (e x +d \right )}{2 d^{3}}+\frac {i \pi \mathrm {csgn}\left (i c \left (b x +a \right )^{p}\right )^{2} \mathrm {csgn}\left (i c \right ) e}{2 d^{2} x}-\frac {i \pi \,\mathrm {csgn}\left (i \left (b x +a \right )^{p}\right ) \mathrm {csgn}\left (i c \left (b x +a \right )^{p}\right )^{2}}{4 d \,x^{2}}+\frac {i \pi \,\mathrm {csgn}\left (i \left (b x +a \right )^{p}\right ) \mathrm {csgn}\left (i c \left (b x +a \right )^{p}\right ) \mathrm {csgn}\left (i c \right )}{4 d \,x^{2}}+\frac {i \pi \mathrm {csgn}\left (i c \left (b x +a \right )^{p}\right )^{3}}{4 d \,x^{2}}+\frac {i \pi \,\mathrm {csgn}\left (i \left (b x +a \right )^{p}\right ) \mathrm {csgn}\left (i c \left (b x +a \right )^{p}\right )^{2} e^{2} \ln \left (x \right )}{2 d^{3}}+\frac {i \pi \mathrm {csgn}\left (i c \left (b x +a \right )^{p}\right )^{3} e^{2} \ln \left (e x +d \right )}{2 d^{3}}-\frac {i \pi \mathrm {csgn}\left (i c \left (b x +a \right )^{p}\right )^{3} e}{2 d^{2} x}-\frac {i \pi \mathrm {csgn}\left (i c \left (b x +a \right )^{p}\right )^{3} e^{2} \ln \left (x \right )}{2 d^{3}}-\frac {i \pi \mathrm {csgn}\left (i c \left (b x +a \right )^{p}\right )^{2} \mathrm {csgn}\left (i c \right )}{4 d \,x^{2}}\) | \(850\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.35, size = 220, normalized size = 0.97 \begin {gather*} \frac {1}{2} \, {\left (2 \, {\left (\frac {\log \left (b x + a\right )}{a d^{2}} - \frac {\log \left (x\right )}{a d^{2}}\right )} e + \frac {b \log \left (b x + a\right )}{a^{2} d} - \frac {b \log \left (x\right )}{a^{2} d} - \frac {2 \, {\left (\log \left (\frac {b x}{a} + 1\right ) \log \left (x\right ) + {\rm Li}_2\left (-\frac {b x}{a}\right )\right )} e^{2}}{b d^{3}} + \frac {2 \, {\left (\log \left (x e + d\right ) \log \left (-\frac {b x e + b d}{b d - a e} + 1\right ) + {\rm Li}_2\left (\frac {b x e + b d}{b d - a e}\right )\right )} e^{2}}{b d^{3}} - \frac {1}{a d x}\right )} b p - \frac {1}{2} \, {\left (\frac {2 \, e^{2} \log \left (x e + d\right )}{d^{3}} - \frac {2 \, e^{2} \log \left (x\right )}{d^{3}} - \frac {2 \, x e - d}{d^{2} x^{2}}\right )} \log \left ({\left (b x + a\right )}^{p} c\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\log {\left (c \left (a + b x\right )^{p} \right )}}{x^{3} \left (d + e x\right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {\ln \left (c\,{\left (a+b\,x\right )}^p\right )}{x^3\,\left (d+e\,x\right )} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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